Question

A friend of mine needs help with the following two problems, but i can't exactly figure out what they want, so I figured you guys could help out.

Answer 1

gl just wanted to saybecuase someone already answered

Explanation:

Answer 2

14)
`x=3`

16)
`(g\circ f)(2)=1`

Explanation:

We have the two functions:
`f(x)=2x-3` and
`g(x)=x^2`.

14)

We want to find x if
`f(x)=3`.

In other words, we want to find for what value of x does f(x) equal 3.

So, to do so, we can substitute our equation,
`2x-3`, for f(x) and solve for x. This gives us:

`2x-3=3`

Solve for x. Add 3 to both sides:

`2x=6`

Divide by 2:

`x=3`

So,
`f(3)=3`, and our x is 3.

16)

We have:
`(g\circ f)(2)`

This is known as composition of functions. This is equivalent to
`g(f(2))`

So, let's find f(2) first. We know that:

`f(x)=2x-3`

Substitute 2 for x:

`f(2)=2(2)-3`

Evaluate:

`f(2)=4-3=1`

Therefore, our composition of functions can be rewritten as:

`g(f(2))=g(1)`

Find g(1). We know that:

`g(x)=x^2`

Substitute 1 for x:

`g(1)=(1)^2`

Evaluate:

`g(1)=1`

Therefore:

`(g\circ f)(2)=1`