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A friend of mine needs help with the following two problems, but i can't exactly figure out what they want, so I figured you guys could help out.

A friend of mine needs help with the following two problems, but i can't exactly figure-example-1
User Abu Aqil
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5.7k points

2 Answers

3 votes

Answer:

gl just wanted to saybecuase someone already answered

Explanation:

User HienPham
by
5.4k points
3 votes

Answer:

14)
x=3

16)
(g\circ f)(2)=1

Explanation:

We have the two functions:
f(x)=2x-3 and
g(x)=x^2.

14)

We want to find x if
f(x)=3.

In other words, we want to find for what value of x does f(x) equal 3.

So, to do so, we can substitute our equation,
2x-3, for f(x) and solve for x. This gives us:


2x-3=3

Solve for x. Add 3 to both sides:


2x=6

Divide by 2:


x=3

So,
f(3)=3, and our x is 3.

16)

We have:
(g\circ f)(2)

This is known as composition of functions. This is equivalent to
g(f(2))

So, let's find f(2) first. We know that:


f(x)=2x-3

Substitute 2 for x:


f(2)=2(2)-3

Evaluate:


f(2)=4-3=1

Therefore, our composition of functions can be rewritten as:


g(f(2))=g(1)

Find g(1). We know that:


g(x)=x^2

Substitute 1 for x:


g(1)=(1)^2

Evaluate:


g(1)=1

Therefore:


(g\circ f)(2)=1

User WhiteEleven
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