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What is the equation of the line perpendicular to y =1/2x+3 passsing through the point (-3,4)?

User Ahocevar
by
6.9k points

2 Answers

3 votes

Final answer:

The slope of the perpendicular line is the negative reciprocal of 1/2, which is -2. Using the point-slope form of a line, the equation is y - 4 = -2(x + 3).

Step-by-step explanation:

To find the equation of a line perpendicular to y = 1/2x + 3 passing through the point (-3,4), we need to determine the slope of the given line.

The slope-intercept form of a line is y = mx + b, where m represents the slope and b represents the y-intercept.

In this case, the slope of the given line is 1/2.

Since the line we want is perpendicular to the given line, its slope will be the negative reciprocal of 1/2.

The negative reciprocal of 1/2 is -2.

Therefore, the slope of the perpendicular line is -2.

Using the point-slope form of a line, which is y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope, we can plug in the values (-3, 4) and -2 to find the equation of the line: y - 4 = -2(x + 3).

User Kpalser
by
6.4k points
1 vote

Answer:

y=-2x-2

Step-by-step explanation:

using Desmos you can see that both equations pass through the point (-3,4)

User Wsorenson
by
7.0k points
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