Final answer:
To prove that the difference between two rational numbers is rational, express r and s as a/b and c/d. Find their difference with a common denominator (bd) to get (ad - bc)/(bd). Since the numerator and denominator are integers and the denominator is not zero, the result is a rational number.
Step-by-step explanation:
The statement to prove is: 'The difference between any two rational numbers is a rational number'. To establish this, let's consider two rational numbers r and s, such that r = a/b and s = c/d, where a, b, c, and d are integers, and b and d are not zero. A rational number by definition can be expressed as the quotient of two integers, with the denominator being non-zero.
The difference of r and s is r - s = (a/b) - (c/d). To combine these two fractions, we find a common denominator which is the product of the two denominators, bd. Rewriting the fractions with the common denominator gives us (ad)/(bd) - (bc)/(bd). Combining these two fractions gives (ad - bc)/(bd).
Now, since both the numerator (ad - bc) and the denominator (bd) are integers, and the denominator bd is not zero (as b and d are both not zero), the number (ad - bc)/(bd) fits the definition of a rational number. Therefore, we have shown that the difference between two rational numbers is itself a rational number.