Question

A 0.420-kg pendulum bob passes through the lowest part of its path at a speed of 3.21 m/s. (a) What is the magnitude of the tension in the pendulum cable at this point if the pendulum is 76.0 cm long

Answer 1

9.81 N

Step-by-step explanation:

Newton's second law states that the acceleration of an object produced by a force is directly proportional to the net force and inversely proportional to its mass.

Hence:

Sum of vertical forces = mass * acceleration

`T-mg=(mv^2)/(r) \\\\g=9.81m/^2,r=76cm=0.78\\\\T-0.42(9.81)=(0.42*3.21^2)/(0.76)\\ \\T-4.12=5.69\\\\T=9.81\ N`