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Calculate the following quantity: molarity of a solution prepared by diluting 49.16 mL of 0.0270 M ammonium sulfate to 525.00 mL.

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Answer:

2.528x10⁻³M

Step-by-step explanation:

Molarity is an unit of concentration used in chemistry. Is defined as the moles of solute per liter of solution.

To find the molarity of the solution we need to determine the moles of ammonium sulfate present in the initial 49.16mL solution and, with total volume, we can find the molarity, thus:

Moles ammonium sulfate:

49.16mL = 0.04916L * (0.0270 moles / L) =

1.327x10⁻³moles ammonium sulfate

These moles are present in 525.0mL = 0.525L. Thus, molarity of the solution will be:

1.327x10⁻³moles ammonium sulfate / 0.525L =

2.528x10⁻³M

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