Question

A tightly wound solenoid is 15 cm long, has 350 turns, and carries a current of 4.0 A. If you ignore end effects, you will find that the value of app at the center of the solenoid when there is no core is approximately

Answer 1

The magnetic field at the center of the solenoid is approximately 0.0117 T

Step-by-step explanation:

Given;

length of the solenoid, L = 15 cm = 0.15 m

number of turns of the solenoid, N = 350 turns

current in the solenoid, I = 4.0 A

The magnetic field at the center of the solenoid is given by;

`B = \mu_o ((N)/(L) )I\\\\B = (4 \pi *10^(-7))((350)/(0.15) )(4.0)\\\\B = 0.0117 \ T`

Therefore, the magnetic field at the center of the solenoid is approximately 0.0117 T.