Question

The freshman spirit club took a trip to the state fair .There were 59 students and 6 chaperones, and the total admission cost for the group was 508$.Student tickets cost 2$ more than the chaperone tickets.Write an equation to represent the cost of a student ticket

Answer 1

Explanation:

First you determine the variables x and y as:

x: the value for student tickets

y: the value for chaperone tickets.

Knowing that student tickets cost $ 2 more than companion tickets, it is represented by the equation:

x= y +2

On the other hand, there were 59 students and 6 companions. And the total cost of admission for the group was $ 508, that is to say that what all the students and the companions have paid adds up to $ 508. Expressed by an equation:

59x + 6y = 508

Then the system of equations to solve and thus obtain the price of a student ticket and the price of a companion ticket is:

`\left \{ {{x=y+2} \atop {59x+6y=508}} \right.`

Solving for x, the price of a student ticket:

Rearranging the first equation,

y = x - 2

Replacing in the second equation and solving for x:

59*x + 6*(x -2)=508

59*x + 6*x -12=508

65*x -12=508

65*x= 508 +12

65*x= 520

`x=(520)/(65)`

x=8

The cost of a student ticket is 8$