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Does anyone know how to solve this 5x(x+4)^2-2y^5 x=-3 and y=-2
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Does anyone know how to solve this 5x(x+4)^2-2y^5 x=-3 and y=-2

User Qiqi
by
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2 Answers

6 votes

Answer:

49

Explanation:

User Busilinks
by
5.9k points
5 votes
It’s 49.
5(-3)(-3+4)^2 -2(-2^5)
5(-3)x 1^2 +2^6
5(-3) x 1 +64
-15+64
=49
User Nagarajan S R
by
7.3k points
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