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Radioactive isotope X has a half-life of 500,000 years. This isotope may be found in some types of volcanic rocks. A particular sample of volcanic rock taken from a layer that covered up some of the earliest known human-like footprints contains 0.125 mg of isotope X. The volcanic rock sample originally contained 8.00 mg of isotope X. How long ago were these footprints made. I need the equation. Thanks. please I am stuck on this question. PLEASE

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Answer: The footprints were made
2.99* 10^6years years long ago.

Step-by-step explanation:

Radioactive decay follows first order kinetics.

Half-life of isotope X= 500,000 years


\lambda =\frac{0.693}{t_{(1)/(2)}}=(0.693)/(500000)=0.00000139year^(-1)

The equation for first order kinetics is :


N=N_o* e^(-\lambda t)

N = amount left after time t = 0.125 mg


N_0 = initial amount = 8.00 mg


\lambda = rate constant

t= time

Putting the values we get:


0.125=8.00* e^{- 0.00000139years^(-1)* t}


0.0156=e^{- 0.00000139years^(-1)* t}


t=2.99* 10^6years

The footprints were made
2.99* 10^6years years long ago.

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