183k views
5 votes
Which of the following scenarios is possible for the resultant velocity of an airplane in a strong wind to be 150 m/s?

A. The wind is blowing at 10 m/s. The airplane is flying against the wind at 140 m/s.

B. The wind is blowing at 20 m/s. The airplane is flying with the wind at 130 m/s.

C. The wind is blowing at 200 m/s. The airplane is flying with the wind at 50 m/s.

D. The wind is blowing at 50 m/s. The airplane is flying against the wind at 100 m/s.​

User Qianyue
by
6.2k points

2 Answers

4 votes

Answer:

B. The wind is blowing at 20 m/s. The airplane is flying with the wind at 130 m/s.

Step-by-step explanation:

User Yflelion
by
6.0k points
0 votes

Answer:

B. The wind is blowing at 20 m/s. The airplane is flying with the wind at 130 m/s.

Step-by-step explanation:

From Physics we get that resultant velocity of an airplane is the sum of an absolute velocity and a relative velocity, that is:


\vec v_(A) = \vec v_(W)+\vec v_(A/W) (Eq. 1)

Where:


\vec v_(W) - Wind velocity, measured in meters per second.


\vec v_(A/W) - Airplance velocity relative to wind, measured in meters per second.


\vec v_(A) - Airplane velocity, measured in meters per second.

If we assume that
\vec v_(W) = 20\,\hat{i}\,\,\,\left[(m)/(s) \right] (The airplane flies with the wind),
\vec v_(A/W) = 130\,\hat{i}\,\,\,\left[(m)/(s) \right], then the resultant velocity of the airplane is:


\vec v_(A) = 20\,\hat{i}+130\,\hat{i}\,\,\,\left[(m)/(s) \right]


\vec v_(A) = 150\,\hat{i}\,\,\,\left[(m)/(s) \right]

Therefore, correct answer is B.

User Moosa
by
5.7k points