Question

The aorta is a major artery, rising upward from the left ventricle of the heart and curving down to carry blood to the abdomen and lower half of the body. The curved artery can be approximated as a semicircular arch whose diameter is 6.1 cm. If blood flows through the aortic arch at a speed of 0.27 m/s, what is the magnitude (in m/s2) of the blood's centripetal acceleration?

Answer 1

2.39m/s2

Step-by-step explanation:

To get the magnitude of the blood's centripetal acceleration in the aortic arch, we use

a = (V^2) / d

where: a = aortic arch's blood's centripetal acceleration

V = the speed of the blood

d = diameter of the aorta

Since it is semicircular of the arch, so we use the radius

So, r = d / 2

V = 0.27 m/s

r = 6.1 cm / 2 = 3.05 cm

convert cm to m (100cm = 1m)

3.05cm / 100cm = 0.0305 m

a = (0.27 m/s)^2 / 0.0305 m

= 0.0729m/s / 0.0305 m

= 2.39m/s2