Question

if 20 ml of carbon dioxide diffuse in 100 second what volume of ozone will diffuse in the same time under similar condition ​

Answer 1

volume of ozone : 19.15 ml

Further explanation

Graham's law: the rate of effusion of a gas is inversely proportional to the square root of its molar masses or

`\tt (r_(CO_2))/(r_(O_3))=\frac{\sqrt{M_(O_3)} }{\sqrt{M_(CO_2)}} }`

rate of CO₂ , M CO₂ = 44,01 g/mol

`\tt r~CO_2=(20~ml)/(100~s)`

• rate of O₃, M O₃ = 48 g/mol

`\tt r~O_3=(x)/(100~s)`

volume of ozone

`\tt \frac{r~{CO_2}}{r~O_3}=(√(48) )/(√(44.01) )\\\\(20)/(x)=(√(48) )/(√(44.01) )\\\\x=(20.√(44.01) )/(√(48) )=19.15~ml`