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2. Solve the system by substitution. (1 point) 2x – y + z = -4 z = 5 -2x + 3y - 2 = -10 O(-8,7,5) O(-8. -7,5) O(8, -7,5) O(-8, -7,-5)

2. Solve the system by substitution. (1 point) 2x – y + z = -4 z = 5 -2x + 3y - 2 = -10 O(-8,7,5) O(-8. -7,5) O(8, -7,5) O(-8, -7,-5)
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2. Solve the system by substitution. (1 point)

2x – y + z = -4
z = 5
-2x + 3y - 2 = -10
O(-8,7,5)
O(-8. -7,5)
O(8, -7,5)
O(-8, -7,-5)

2. Solve the system by substitution. (1 point) 2x – y + z = -4 z = 5 -2x + 3y - 2 = -10 O-example-1
User Gregroy
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8.4k points

1 Answer

4 votes

Answer:

Answer for this one is second one (-8,-7,5)

Explanation:

Hope it will help you :)

User Sloan Thrasher
by
8.7k points
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