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Find two consecutive even integers

such that twice the larger is 14 less
than 5 times the smaller.





help me

Find two consecutive even integers such that twice the larger is 14 less than 5 times-example-1

1 Answer

3 votes
You can set up a system of equations with x being the smaller number and y being the larger number. So the first equation would be 2y=5x-14 and the second equation would be x=y-2. You can solve by substitution and substitute y-2 into the x in the first equation to get 2y=5(y-2)-14. You can solve this out and it ends up simplifying to y=8. So you know the larger number is 8. So since the larger number is 8 and they are consecutive even integers, the smaller number must be 6. So the two numbers would be 6 and 8.
User Tim Hallyburton
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