Question

426429418417422435420410432435423426409437436429411426411438422428413414Consider this data as a sample of the population.(a) Calculate a point estimate of the mean oxide thickness for all wafers in the population. (Round your answer to 3 decimal places.)(b) Calculate a point estimate of the standard deviation of oxide thickness for all wafers in the population. (Round your answer to 2 decimal places.)(c) Calculate the standard error of the point estimate from part (a). (Round your answer to 2 decimal places.)(d) Calculate a point estimate of the median oxide thickness for all wafers in the population. (Express your answer to 1 decimal places.)(e) Calculate a point estimate of the proportion of wafers in the population that have oxide thickness greater than 430 angstrom. (Round your answer to 4 decimal places.)(a) The point estimate of the mean oxide thickness is Entry field with correct answer424.091 Angstroms.(b) The point estimate of the standard deviation of oxide thickness is Entry field with incorrect answer Angstroms.(c) The point estimate of the standard error of the mean is Entry field with incorrect answer Angstroms.(d) The point estimate of the median oxide thickness is Entry field with incorrect answer417.5 Angstroms.

Answer 1

Kindly check explanation

Explanation:

Given the data:

426 429 418 417 422 435 420 410 432 435 423 426 409 437 436 429 411 426 411 438 422 428 413 414

A) Point estimate of the mean(m) : (ΣX) /n

Sample size(n) = 24

(426+429+418+417+422+435+420+410+432+435+423+426+409+437+436+429+411+426+411+438+422+428+413+414) / 24

= 10167 / 24

= 423.625 (3 decimal places)

b) Calculate a point estimate of the standard deviation of oxide thickness for all wafers in the population

s = √[Σ(X - m)² / (n - 1)]

Using calculator :

s = 9.277

s = 9.28 ( 2 decimal places)

C.)

Standard Error of point estimate :

SE = s/√n

SE = 9.28 / √24

SE = 1.8942720

(d) Calculate a point estimate of the median oxide thickness for all wafers in the population.

Median = 0.5 (n +1)th term

0.5(25) = 12.5th term ;

(12th + 13 th term)/2

(423 + 426) / 2

= 849/2

= 424.5

(e) Calculate a point estimate of the proportion of wafers in the population that have oxide thickness greater than 430 angstrom

Number of oxide thickness greater than 430 = 6

(number greater than 430 / total number of oxides)

= 6 / 24

= 1/4

= 0.25