Answer:
There 68 bicycles , 33 tricycles and 17 Tandem bicycles
Explanation:
Let B be the no. bicycles , TB be the no. of tandem bicycles and C be the no. of tricycles
No. of seats in 1 bicycle = 1
No. of seats in B bicycle = B
No. of seats in 1 Tandem bicycle = 2
No. of seats in TB Tandem bicycle = 2TB
No. of seats in 1 Tricycle = 1
No. of seats in C Tricycle = C
We are given that There are a total of 135 seats
So, B+2TB+C=135 ----1
Similarly
There are total 118 front handlers
So,1B + 1TB + 1C = 118 ----2
There are total 269 wheels
So,2B + 2TB + 3TR = 269
Substract 1 from 2
B+2TB+C-B-TB-C=135-118
TB=17
Adding 1 and 2 and substracting from 3
[2 - (1+1)]B + [2- (2+1)]TB + [3- (1+1)]C = 269-253
- 1x17 +C= 16
C= 16 + 17 = 33
Replacing in eq. 32
1B + 17 + 33 = 118
B = 118 - 17 - 33 = 68
Hence There 68 bicycles , 33 tricycles and 17 Tandem bicycles