Question

A club of 50 students is doing volunteer. Each student is volunteering at one of four location. 14 at the hospital, 15 at the pet shelter, 8 at tutoring, 13 at library. What is the probability that the first student volunteers at the library and the other two do not?

Answer 1

The probability is 0.1473

Explanation:

Given;

total number of students, n = 50

number at hospital, h = 14

number at pet shelter, p = 15

number at tutoring, t = 8

number at library, L = 13

If three students are chosen at random without replacement, the number of students that will be selected to work in other location is given by;

50 - 13 = 37 students

The probability that the first student volunteers at the library and the other two do not is given by;

P(13 students at library) x P(2 out of the 37 students did not)

`= ((13)/(50))((37)/(49))((36)/(48) )\\\\ = 0.1473`