Answer:
The critical value is
![t_{(0.10)/(2) , 14 } =[ - 1.761,1.761]](https://img.qammunity.org/2021/formulas/mathematics/college/s9b0ua5xlamma6mz7ea0506079vqq3rix3.png)
Explanation:
From the question we are told that
The sample size is n = 15
The level of significance is
![\alpha = 0.10](https://img.qammunity.org/2021/formulas/engineering/college/jps3unr82c4ioxfx6y9497rl6wkf1r013l.png)
The null hypothesis is
![H_o : \mu _1 = \mu_2](https://img.qammunity.org/2021/formulas/mathematics/high-school/bo4sf3eu6xcoh0xb0wxpq0bumasvxkqejr.png)
The alternative hypothesis is
![H_a : \mu_1 \\e \mu_2](https://img.qammunity.org/2021/formulas/mathematics/college/d2xpp4x42xir2p8ku3vckclh35qfh0kbov.png)
Here
is average time for previous year
is the average time for current year
Generally the degree of freedom is mathematically represented as
![df = n -1](https://img.qammunity.org/2021/formulas/mathematics/college/ut1kcbmb8gmcd640z8ht7t5b6d7s2xoqmm.png)
=>
![df = 15 - 1](https://img.qammunity.org/2021/formulas/mathematics/college/2nugjqz906fl7hlgb6gal2wmb7n2u2rmpd.png)
=>
![df = 14](https://img.qammunity.org/2021/formulas/mathematics/college/6pn7qp8q35fy187vbnl48gdirx4b2ytfxr.png)
Generally from the student t distribution table the critical value for
at a degree of freedom of
for a two tailed test is
![t_{(0.10)/(2) , 14 } =[ - 1.761,1.761]](https://img.qammunity.org/2021/formulas/mathematics/college/s9b0ua5xlamma6mz7ea0506079vqq3rix3.png)