Question

The boiling point of water is 100.0*C, yet a student measured it to be 101.3*C. Calculate the percent error of the student's measurement.

Answer 1

Percent error = 1.3%

Step-by-step explanation:

Given data:

Actual value of boiling point = 100.0 °C

Measured value = 101.3 °C

Percent error = ?

Solution:

Formula:

Percent error = ( Measured value - Actual value / Actual value ) × 100

Now we will put the values in formula.

Percent error = 101.3 °C - 100.0 °C / 100.0 °C × 100

Percent error = 1.3 °C / 100.0 °C × 100

Percent error = 0.013 × 100

Percent error = 1.3%

Thus, percent error is 1.3.