Answer:
0.028%
Step-by-step explanation:
From the question given above, the following data were obtained:
Accepted value = 4.6026 g
Measured value = 4.6013 g.
Percentage error =..?
Thus, we can obtain the percentage error in the student's reading as follow:
Percentage error = |measured value – accepted value|/accepted value × 100
Percentage error = |4.6013 – 4.6026| / 4.6026 × 100
Percentage error = 0.0013 / 4.6026 × 100
Percentage error = 0.13/4.6026
Percentage error = 0.028%
Therefore, the percentage error in the student's reading is 0.028%