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Solve this application problem using a system of equations: 40,000 people attended a ballgame at a stadium that offers two kinds of seats: general admission and reserved. The day's receipts were $425,000. How many people paid $15.00 for reserved seats, and how manypaid $8.00 for general admission?

User Lilactown
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Answer: 15,000 people paid $15.00 for reserved seats and 25,000 paid $8.00 for general admission.

Explanation:

Let x = Number of reserved seats

y= Number of general admission

According o the question:

x + y = 40000 (i)

15x + 8 y = 425000 (ii)

Multiply 8 to equation (i), we get

8x + 8 y = 320000 (iii)

Subtract (iii) from (ii), we get

15x - 8x + 8y - 8y = 425000-320000

⇒ 7x = 105000

⇒ x = 15000 [Divide both sides by 7]

Put this in (i) , we get

15000+y= 40000

⇒ y = 40000-15000

⇒ y= 25000

Hence, 15,000 people paid $15.00 for reserved seats and 25,000 paid $8.00 for general admission.

User Dan Snell
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