Answer:
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Explanation:
Let the number be x
Given condition:
x² = 4x - 3
Subtract 4x to both sides and add 3 to both sides
x² - 4x + 3 = 0
Using mid-term break
x² - 3x - x + 3 = 0
Take common
x(x-3) - 1(x-3) = 0
Take (x-3) common
(x - 3)(x - 1) = 0
Using zero's method
Either,
x - 3 = 0 OR x - 1 = 0
x = 3 OR x = 1
![\rule[225]{225}{2}](https://img.qammunity.org/2023/formulas/english/college/eq413d752mwtrwwenrzwldxt4w1olmf1b3.png)