Question

If p(x) = x2 - 1 and 9(x) = 5(x - 1), which expression is equivalent to (0-9)(x)?

5(x - 1) - x2 - 1
(5x-1) - (x² - 1)
(x2 - 1) - 5(x - 1)
(x2 - 1) - 5x-1

Answer 1

x^2 -1 - 5(x-1)

Explanation:

p(x) = x^2 - 1 and q(x) = 5(x - 1)

p(x) - q(x) = x^2 - 1 - ( 5(x-1))

Distribute

= x^2 -1 - 5(x-1)