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Find dy/dx in terms of x and y

3x sin y + 2 cos y = sin x​

User Markoorn
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1 Answer

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3x\sin y+2\cos y=\sin x


(\mathrm d(3x\sin y+2\cos y))/(\mathrm dx)=(\mathrm d(\sin x))/(\mathrm dx)


(\mathrm d(3x))/(\mathrm dx)\sin y+3x(\mathrm d(\sin y))/(\mathrm dx)+(\mathrm d(2\cos y))/(\mathrm dx)=\cos x


3\sin y+3x\cos y(\mathrm dy)/(\mathrm dx)-2\sin y(\mathrm dy)/(\mathrm dx)=\cos x

Solve for dy/dx :


3\sin y+\left(3x\cos y-2\sin y\right)(\mathrm dy)/(\mathrm dx)=\cos x


\left(3x\cos y-2\sin y\right)(\mathrm dy)/(\mathrm dx)=\cos x-3\sin y


(\mathrm dy)/(\mathrm dx)=\boxed{(\cos x-3\sin y)/(3x\cos y-2\sin y)}

User Constructor
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