Question

What's the required mass of (NH4)2SO4 needed to make a 250 mL solution at a concentration of 6 M?

MM = 132.1 grams/mole

Answer 1

The required mass would be 198.15g

Step-by-step explanation:

No of moles = mass ÷ molar mass

No of moles = concentration × volume

concentration = 6M

Molar mass= 132.1 grams/mole

Volume = 250mL= 0.25L

No of moles = 6 × 0.25 = 1. 5 moles

Mass = no of moles × Molar mass

Mass = 1.5 × 132.1

Mass = 198. 15g

The required mass is 198.15g