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If an arithmetic sequence has a 10th term of 17 and a 14th term of 30. find the common difference.​

User Gzost
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1 Answer

7 votes

Answer:


\bold{d=\frac{13}4=3\frac14}

Explanation:


a_(10)\,,\ _{\{+d\}}\ \ a_(11)\,,\ _{\{+d\}}\ \ a_(12)\,,\ _{\{+d\}}\ \ a_(13)\,,\ _{\{+d\}}\ \ a_(14)\quad\implies\quad\ a_(14)-a_(10)=4d\\\\4d=a_(14)-a_(10)\\\\4d=30-17\\\\4d=13\\{}\ ^(/4\quad/4)\\d=\frac{13}4=3\frac14

User Curiousdork
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