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A number of compounds containing the heavier noble gases, and especially xenon, have been prepared. One of these is xenon hexafluoride (XeF6), which can be prepared by heating a mixture of xenon and fluorine gases. XeF6 is a white crystalline solid at room temperature and melts at about 325 K. A mixture of 0.0600 g of Xe and 0.0310 g of F2 is sealed into a 100.0-mL bulb. The bulb contains no air or other gases. The bulb is heated, and the reaction above goes to completion. Then, the sealed bulb is cooled back to 20.0°C. What will be the final pressure in the bulb, expressed in torr?

User Fatcook
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Answer:

The answer is "82.2 torr"

Step-by-step explanation:

moles of Xe:


= (0.06)/(131.293) \\\\ =0.00045699313 \ \mol

moles of
F_2:


= (0.0274)/(38) \\\\= 0.00072105263\ \ mol

moles of produced
XeF_2:


= 0.00024

moles of left
Xe:


= 0.00021

Calculate the Pressure:


= ((0.08206* 0.00024 * 293))/((.1)) + ((0.08206* 0.00021 * 293))/((.1)) \\\\= 0.10819611 \ \ atm \\\\ = 0.10819611 * 760 \\\\ = 82.2 \ \ torr

User LindaQ
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