Answer:
Explanation:
Let's say :
v = number students in van, b = number of students in bus
From the info provided in the question:
High school A takes 3 vans and 14 buses for 509 students
We can write this as:
3v + 14b = 509
You can re-write this as :
3v = 509 - 14b
We also know High School B takes 12 vans and 10 buses for 472 students:
12v + 10b = 472
Since we already know that 3v = 509 - 14b , substitute this equation into the above formula and you get:
12v + 10b = 472
4(509 - 14b) + 10b = 472
2036 - 56b + 10b = 472
2036 - 46b = 472
2036 - 472 = 46b
1564 = 46b
Divide both sides by 46 to find "b".
b = 1564/ 46 = 34
Therefore the number of students that fit in each bus is 34.
So since we know b = 34, substitute b into the equation at the top:
3v = 509 - 14b
3v = 509 - 14(34)
3v = 509 - 476 = 33
Divide both sides by 3 to find "v".
v = 33/3 = 11.
Therefore the number of students in each van is 11.