Question

Write the equation of a Line that is perpendicular to y=5/2x+3 and passes

through point (-3,-5)? *

Answer 1

Explanation:

Slope of perpendicular lines = -1

y = 5/2x + 3

`m_(1)=(5)/(2)\\\\m_(1)*m_(2)=-1\\\\`

`m_(2)=` -1 ÷
`m_(1)`

=
`-1*(2)/(5)=(-2)/(5)`

(-3 , -5)

Equation of the required line: y - y₁ = m(x -x₁)

y - [5] =
`(-2)/(5)(x - [-3])\\`

`y+5=(-2)/(5)x + 3*(-2)/(5)\\\\y+5=(-2)/(5)x-(6)/(5)\\\\ y =(-2)/(5)x-(6)/(5)-5\\\\ y = (-2)/(5)x-(6)/(5)-(5*5)/(1*5)\\\\ y = (-2)/(5)x-(6)/(5)-(25)/(5)\\\\\\ y=(-2)/(5)x-(31)/(5)`