Question

A tiger leaps horizontally froma 7.5 m high rock with a speed of 3.0 m/s. How far from the base of the rock will she land?

Answer 1

The tiger will land at 3.71 meters from the base of the rock

Step-by-step explanation:

Horizontal Motion

When an object is thrown horizontally with a speed vo from a height h, the range or maximum horizontal distance traveled by the object can be calculated as follows:

`\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}`

The tiger leaps from a height of h=7.5 m with a speed of v=3 m/s. Substituting the values into the formula:

`\displaystyle d=3\cdot\sqrt{\frac {2\cdot 7.5}{9.8}}=3.71\ m`

The tiger will land at 3.71 meters from the base of the rock