Find the H.C.F of a²+7a+10,a²+6a+8anda²+9a+20

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asked May 18, 2021 84.8k views

1 vote

Find the H.C.F of a²+7a+10,a²+6a+8anda²+9a+20

Mathematics
high-school

Justin Pavatte asked

by Justin Pavatte

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1 Answer

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Answer:

a²+7a+10=0

(a+2)(a+5)=0

∴a+2=0

a= -2

a+5=0

a= -5

a²+6a+8=0

(a+2)(a+4)=0

∴a+2=0

a= -2

a+4=0

a= -4

a²+9a+20

(a+4)(a+5)

∴a+4=0

a= -4

a+5=0

a= -5

Explanation:

Solution on the Math book

Iwona answered May 25, 2021

by Iwona

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