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The "cold start ignition time" of an automobile engine is being investigated by a gasoline manufacturer. The following times (in seconds) were obtained for a test vehicle: 1.75, 1.92, 2.62, 2.35, 3.09, 3.15, 2.53, and 1.91. (a) Calculate the sample mean and sample standard deviation. (b) Construct a box plot of the data.

User Erebus
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Answer:

(a) The sample mean and sample standard deviation are 2.415 and 0.5342 respectively.

(b) Shown below.

Explanation:

The data set provided is:

S = {1.75, 1.92, 2.62, 2.35, 3.09, 3.15, 2.53, and 1.91}

(a)

Compute the sample mean and sample standard deviation as follows:


\bar x=(1)/(n)\sum\limits_(i){x_(i)} =(1)/(8)* 19.32=2.415\\\\\\s=\sqrt{(1)/(n-1)\sum\limits_(i){(x_(i)-\bar x^(2))^(2)}}=\sqrt{(1)/(8-1)* 1.9976}=0.5342

Thus, the sample mean and sample standard deviation are 2.415 and 0.5342 respectively.

(b)

Use SPSS to form a Box plot.

Go to Graphs → Legacy Dialogs → Boxplot

A dialog box will open.

Select "Simple".

Select "Summaries for Separate Variable"

Press "Define"

Another dialog box will open.

Select the variable.

Press OK.

The box plot is attached below.

The "cold start ignition time" of an automobile engine is being investigated-example-1
User AYBABTU
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