Question

What is the equation of the line, in slope-intercept form, that passes through point (-2, 5) and is parallel to the line whose equation is x + y = 10?

y = x - 3
y = - x + 3
y = x + 3

Answer 1

y= -x+3

Explanation:

Take the slope from x + y = 10, which is -1. Your equation should look like y = (-1)x + b where "b" is the y-intersect. Substitute your "y" and "x" values from the point into the equation so it looks like 5 = (-1)(-2) + b, and solve for b=3. The put it together to get y= -x+3.