Question

A 60kg woman on skates throws a 3.9kg ball with a velocity of

37m.s west. What is the velocity of the woman?

Answer 1

2.405 m/s

Step-by-step explanation:

Given that,

Mass of a women, m₁ = 60 kg

Mass of a ball, m₂ = 3.9 kg

Velocity of the ball, v₂ = 37 m/s

We need to find the velocity of the woman. It is a concept based on the conservation of linear momentum. Let v₁ is the velocity of the woman. So,

`m_1v_1=m_2v_2\\\\v_1=(m_2v_2)/(m_1)\\\\v_1=(3.9* 37)/(60)\\\\v_1=2.405\ m/s`

So, the velocity of the woman is 2.405 m/s.