Question

You would like to find the density of an unusually shaped piece of jewelry. Since the piece of jewelry has an irregular shape, you need to use displacement to calculate the volume. In a 300 ml beaker you pour 200 ml. Of water. When you place the piece of jewelry in the beaker, the water level rises to 278 ml. Upon placing the object on the triple beam balance, you find that it weighs 122 grams. Given this information, calculate the density. SHOW YOUR WORK

Answer 1

Volume displaced by jewelry, V = 278 - 200 = 78 ml

Also, 1 ml = 1 cm³

We know, by water displacement method the volume of water displaced by an object it equals to its own volume.

So, volume of jewelry, V = 78 ml = 78 cm³.

Also, weight of jewelry is , w = 122 gm.

Now, we know density is given by :

`d=(w)/(V)\\\\d=(122\ gm)/(78\ cm^3)\\\\d=1.56\ gm/ cm^3`

Hence, this is the required solution.