Question

1. A Mars rover is packed inside an airbag lander that will bounce on the surface of the planet. The rover will bounce many times before coming to a stop. It is projected that on the first bounce, the lander will project upward at 75° above the horizon with a speed of 9.92m/s. A. How much time will elapse between this first bounce and the second bounce

Answer 1

The value is
`t = 5.15 \ seconds`

Step-by-step explanation:

From the question we are told that

The angle is
`\theta  =  75^o`

The speed is
`v  =  9.92 \  m/s`

The time taken is mathematically represented as

`t =  ( 2 * v * sin (\theta ))/( g)`

=>
`t =  ( 2 *9.92 * sin (75 ))/( 9.8)`

=>
`t = 5.15 \ seconds`