Question

A container of hydrogen at 172 kPa was decreased to 85.0 kPa producing a new volume of 3L. What was the original volume?

Answer 1

The answer is 1.48 L

Step-by-step explanation:

In order to find the original volume we use the same for Boyle's law which is

`P_1V_1 = P_2V_2`

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the original volume

`V_1 = (P_2V_2)/(P_1) \\`

From the question

P1 = 172 kPa = 172000 Pa

P2 = 85 kPa = 85000 Pa

V2 = 3 L

We have

`V_1 = (85000 * 3)/(172000) = (255000)/(172000) = (255)/(172) \\ = 1.482558139...`

We have the final answer as

1.48 L

Hope this helps you