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Find two consecutive odd numbers such that the sum of the larger number and twice the smaller number is 27 less then foir times the smaller number

User Samy Vilar
by
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1 Answer

0 votes

Answer:

29 and 31

Explanation:

x - some integer

2x+1 - an odd integer (the smaller one)

2x+1+2=2x+3 - the next odd integer consecutive to 2x+1 (the larger)

2×(2x+1) - twice the smaller number

2x+3+2•(2x+1) -the sum of the larger number and twice the smaller number

4•(2x+1) - four times the smaller number

4•(2x+1)-27 - 27 less then four times the smaller number

2x + 3 + 2•(2x + 1) = 4•(2x + 1) - 27

2x + 3 + 4x + 2 = 8x + 4 - 27

6x + 5 = 8x - 23

-5 -5

6x = 8x - 28

-8x -8x

-2x = - 28

÷(-2) ÷(-2)

x = 14

2x+1 = 2•14 + 1 = 29

2x+3 = 2•14 + 3 = 31

Check: 31+2•29=31+58=89; 4•29-27=116-27=89

User Kesem David
by
6.8k points
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