Final answer:
The frequency of a photon with an energy of 3.03 x 10^-19 J is approximately 4.58 x 10^14 Hz.
Step-by-step explanation:
The formula to calculate the energy of a photon is E = hf, where the constant of proportionality h is Planck's constant.
To find the frequency of a photon, we can rearrange the formula as f = E/h. Plugging in the given energy value of 3.03 x 10^-19 J and Planck's constant value of 6.63 x 10^-34 J·s, we get f = (3.03 x 10^-19 J) / (6.63 x 10^-34 J·s) ≈ 4.58 x 10^14 Hz.
Therefore, the frequency of the photon is approximately 4.58 x 10^14 Hz. The correct answer is option b.