185k views
1 vote
Determine the solution for x^2-3x-28 > or equal to 0

User Jeevs
by
4.7k points

2 Answers

6 votes
The solutions are:
x = −4,x = 7
Step-by-step explanation:
X^2−3x−28= 0
We can first factorise this expression by splitting the middle term and then find the solutions:
= x^2−7x+4x−28=0

= x( x−7) + 4( x − 7)=0
=(x+4)(x−7)
Now, we can equate the two factors with zero and find the solutions:
x+4=0,x =−4x−7=0,x=7
User Smottt
by
5.0k points
4 votes

Answer:

C (-∞, -4] [7,∞)

User Sei
by
5.0k points
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