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Two planes are about to drop an empty fuel tank. At the moment of release each plane has the same speed of 195 m/s, and each tank is at the same height of around 1.10 km above the ground. Although the speeds are the same, the velocities are different at the instant of release, because one plane is flying at an angle of 15° above the horizontal (Plane A) and the other is flying at an angle of 15° below the horizontal (Plane B).

1. Find the:

a. magnitude.
b. direction of the velocity with which the fuel tank hits the ground if it is from plane A.

2. Find the:

a. magnitude
b. direction of the velocity with which the fuel tank hits the ground if it is from plane B.

In each part, give the direction as a positive angle with respect to the horizontal.

User Curlywei
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1 Answer

2 votes

Answer:

376.71

Step-by-step explanation:

1.a

To find the angle between them we add 15 +15=30°

Since they aren't perpendicular we use cosine law


\alpha = 180 - 30


\sqrt{ {a}^(2) + {b}^(2) - 2ab \cos( \alpha ) }


\sqrt{ {195}^(2) + {195}^(2) - 2 * 195 * 195 * \cos(150) }

=376.711

User Justin AnyhowStep
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7.3k points