Answer:
T = (99.78 ±0.05) ºC
Step-by-step explanation:
This problem refers to the procedure to perform the measurements and their correct reporting.
Suppose that the thermometer used has an appreciation of 0.1ºC and the values of 5 measurements resulted in
# T (ºC)
1 99.8
2 99.7
3 99.7
4 99.8
5 99.9
the processing calculate mean value
T_average = ∑
/ n
T_average = (99.8 + 99.7 + 99.7 + 99.8 + 99.9) / 5
T_average = 99.78ºC
the absolute error or uncertainty of the measurement is half the appreciation of the instrument
ΔT = ± 0.05ºC
so the result must be written
T = (99.78 ±0.05) ºC