Question

P=16,000,r=4%,t=25 years;compounded continuously

Answer 1

`~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^(rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$16000\\ r=rate\to 4\%\to (4)/(100)\dotfill &0.04\\ t=years\dotfill &25 \end{cases} \\\\\\ A=16000e^(0.04\cdot25)\implies A=16000e\implies A\approx 43492.51`