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Find the zeros of each function by factoring. f(x)=2x^2-7x-4 plzzz helpp meeee plzz

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2x^2 - 7x - 4
Multiply 2 and 4
x^2 - 7x - 8
(x - 8) (x + 1)
Divide by 2 for both numbers to bring the 2 back that was multiplied
(x - 4) (2x + 1)

(x - 4)
x - 4 = 0
+4 on both sides
x = 4

(2x + 1)
2x + 1 = 0
-1 on both sides
2x = -1
/2 on both sides
x = -1/2

Answer:
x = 4
x = -1/2
User Joseph Larson
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