Question

How do you do this question?

Answer 1

-3/16

Explanation:

x = 6 + t²

y = t² + t³

dx/dt = 2t

dy/dt = 2t + 3t²

dy/dx = (2t + 3t²) / 2t

dy/dx = 1 + 1.5t

d²y/dx² = d(dy/dx)/dt / (dx/dt)

d²y/dx² = (1.5) / (2t)

d²y/dx² = 3 / (4t)

At t = -4:

d²y/dx² = 3 / (4 × -4)

d²y/dx² = -3/16