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19 votes
How to find the root of x^2 -6x+8=0

User Chomeh
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2 Answers

28 votes
28 votes

Answer:

x = 4 and x = 2

Explanation:

The easiest way to find the roots is by converting the function into its factored form. This can be determined by asking the question:

What two numbers have a product 8 and a sum of -6?

These two values are -4 and -2.

-4 x -2 = 8

-4 + (-2) = -6

These two numbers are used in the factored form of the equation. You can prove the accuracy of the factored form by re-expanding it (multiply all the terms in the first parentheses by the terms in the second parentheses). The factored form looks like this:

(x - 4)(x - 2)

The roots are the values that make the expression equal 0. This can be done by setting each parentheses equal to 0 and solving for "x".

x - 4 = 0 x - 2 = 0

x = 4 x = 2

Therefore, the roots of the function x² - 6x + 8 are x = 4 and x = 2.

User Rob Nemeth
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3.0k points
23 votes
23 votes

Answer:

2,4

Explanation:

This question is quite simple. First you need to find the factors of 8. Then you need to see which factors of positive 8 can add up to make -6. The factors are -4 and -2. Then expand. Now you have the equation x^2-4x-2x+8. Now group it.

(x^2-4x) +(-2x+8)

Then take out the X from the first group and the -2 from the second. We want the values in the brackets to be the same.

Now you have

x(x-4)-2(x-4)

Take the x and the -2x and make it a group. Now you have (x-4)(x-2)

Set x-4 equal to zero. x-4=0 Now solve it like a regular equation. Add four to both sides. Now you have x=4

Do the same thing with (x-2) and you get x=2

4 and 2 are your solutions

User Slitvinov
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3.0k points