Question

(-2,0) and (3,4)

slope=1/3 and (2,4)

SOLVE EQUATIONS FOR THEM PLEASE

Answer 1

Answer:
`a)\quad y=(4)/(5)x+(8)/(5)`
`b)\quad y=(1)/(3)x+(10)/(3)`

Explanation:

Use the Slope formula:
`m=(y_2-y_1)/(x_2-x_1)`

and the Point-Slope formula: y - y₁ = m(x - x₁)

a) (-2, 0) and (3, 4)

`m=(0-4)/(-2-3)\quad =(-4)/(-5)\quad =(4)/(5)`

Let (x₁, y₁) = (-2, 0)

y - y₁ = m(x - x₁)

`y-0=(4)/(5)\bigg(x-(-2)\bigg)\\\\\\y\quad =(4)/(5)\bigg(x+2\bigg)\\\\\\\large\boxed{y\quad =(4)/(5)x+(8)/(5)}`

b) m = 1/3 (x₁, y₁) = (2, 4)

y - y₁ = m(x - x₁)

`y-4=(1)/(3)\bigg(x-2\bigg)\\\\\\y-4 =(1)/(3)x-(2)/(3)\\\\\\y\quad \ =(1)/(3)x-(2)/(3)+(12)/(3)\\\\\\\large\boxed{y\quad =(1)/(3)x+(10)/(3)}`