Question

What is the value of F in this equation

F^2=9/49

Answer 1

`\sqrt{f {}^(2) } = \sqrt{ (9)/(49) }`

`f = ( √(9) )/( √(49) )`

`f = (3)/(7)` or -3/7

Answer 2

`f=-(3)/(7),(3)/(7)`

Explanation:

`f^2=(9)/(49)`

Square root both sides of the equation:

`√(f^2) =\sqrt{(9)/(49) }`

The square root of
`f^2` is
`f`, so let's rewrite the equation:

`f=\sqrt{(9)/(49) }`

Now, we can make this easier on ourselves by noticing that both the numerator and denominator of the fraction are square numbers, so rewrite the equation:

`f=(√(9) )/(√(49))`

Find the square root of 9 (-3 & 3), and the square root of 49 (-7 & 7). Due to the possibility of the positive or negative solution, there will be two:

`f=-(3)/(7) ,(3)/(7)`