18.0k views
4 votes
What is the value of x, if the perimeter of the rectangle is 37?

This is the problem :

What is the value of x, if the perimeter of the rectangle is 37? This is the problem-example-1

1 Answer

4 votes

Answer:

X= 3.7

Explanation:

Perimeter of rectangle= 2(L+B)

37= 2(4X+X)

37= 2(5X)

37= 10X

37/10=X

3.7= X

User Sven Erik Knop
by
7.4k points