Question

What is the value of "a" in the following quadratic? (Make sure the equation is in

standard form: ax² + bx+c=0)
x^2 + 28 = -11x

Answer 1

Answer: a= -
`(b)/(x)`-
`(c)/(x2)`

Explanation:

1. Move all terms not containing
`\alpha` to the right side of the equation.

`\alpha`
`x^(2)`=-bx-c

2. Divide each term in
`\alpha x^(2)`=-bx-c by
`x^(2)` and simplify.

a= -
`(b)/(x)` -
`(c)/(x^(2) )`